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 How many nsec can be created before they run out?  Does anyone have the math on this? 

#AskNostr 
 Lol 
 25 
 69420
 
 The answer is 2^256 
 If your answer is correct, that would be: 

115 quattuorvigintillion 792 trevigintillion 89 duovigintillion 237 unvigintillion 316 vigintillion 195 novemdecillion 423 octodecillion 570 septendecillion 985 sexdecillion 8 quindecillion 687 quattuordecillion 907 tredecillion 853 duodecillion 269 undecillion 984 decillion 665 nonillion 640 octillion 564 septillion 39 sextillion 457 quintillion 584 quadrillion 7 trillion 913 billion 129 million 639 thousand 936 
 Its a very big number 
 10^(256*log(2)/log(10)) ≈ 10^77 
 Because of reflections and a few invalid keys at the very top, it is only about half that.

So closer to 57896044618658097711785492504343953926634992332820282019728792003956564819968 
 I wondered if i'd get away with not mentioning that lol 
 Way more than the number of atoms in the universe. 

I’d estimate something like (26+26+10)^length of key, which is like what, 64 characters? So ballpark (2^6)^64 which is like 2^384 or ballpark 10^100+