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 A little guess on it, the 10 letters b, d, k, l, r, v, w, x, y, z do not appear in this character set, therefore, among the 2048 words in BIP-39, cut the first 4 letters out first, and then delete all the words containing these 10 letters, leaving only about 600 candidate words.
 On the other hand, to uniquely express 12 seed words, each taking the first 4 letters requires 48 letters. Only 46 are given here. Therefore, there are, and only 2 words that are 3 letters long, and there are 10 words are 4 letters in length.
 If this guess is correct, it should be feasible to run a letter counting program for random combinations of 12 words on the compiled 600-length word list, but this may cause collisions, different combinations may produce the same letter count.
FYI. 
 Very well done! Yes, there 10 4 letter words and 2 three letter words:) What I have provided are the first 4 or 3 letters of each word. 
 OH! It is 10 4's and 2 3's? My short list just got WAYYYY shorter to 139 words. 
 If there are 10, 4 letter words and 2, 3 letter words. How come the last 12 word is mother???

What I'm not understanding here?  
 They are truncated, you only need the first 4 letters of BIP-39 seed words:) 
 Oh that's right 💡 
 Hmm... But still, if I extracted  all the words which have these specified characters as their first 3-4 characters I get 602 words which gives me 3 nonillion combinations (3*10^30) even if we have a clue word for the last word.

I call this #uncypherable with a decent home computer

I wander how others get to such lower number of words? 
 
 It was here :) nostr:nevent1qqstzxutfyjylvkaukgwuyt4kl8ht3m2z2x8czq2uw7aen662zu45sqpr9mhxue69uhhyetvv9ujumn0wd68yct5dyhxxmmd9upzpknx6csaqkah5ltycxklur4xggw20kmq6yyfekvtqmx0e5829mtcqvzqqqqqqykra5nw 
 Ah yes sorry I could have worded that better, although I did say first 4 in second sentence https://i.nostr.build/roZe2.jpg  
 No worries at all! I see what you mean now. Thanks for clarifying and providing the link. Much appreciated! 😊👍 
 My original words are about a method: 
1. among the 2048 words in BIP-39, cut the first 4 letters out first
2. delete all the words containing these 10 letters, leaving only about 600 candidate words.
3. to uniquely express 12 seed words, each taking the first 4 letters requires 48 letters. Only 46 are given here, so there are 2 words that are 3 letters long, and there are 10 words are 4 letters in length.
4.  run a letter counting program for random combinations of 12 words on the compiled 600-length word list

It's hard to understand from these words that all seed words longer than 4 letters are excluded, right? 
 No worries at all! I see what you mean now. Thanks for clarifying and providing the link. Much appreciated! 😊👍 
 My original words are about a method: 
1. among the 2048 words in BIP-39, cut the first 4 letters out first
2. delete all the words containing these 10 letters, leaving only about 600 candidate words.
3. to uniquely express 12 seed words, each taking the first 4 letters requires 48 letters. Only 46 are given here, so there are 2 words that are 3 letters long, and there are 10 words are 4 letters in length.
4.  run a letter counting program for random combinations of 12 words on the compiled 600-length word list

It's hard to understand from these words that all seed words longer than 4 letters are excluded, right?