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Grigory Shepelev | 1 years ago (raw) | root | parent | reply | flag 
 @c39d2605 @4c603b88 @462ebf4c set! Won't affect `f` from `X`
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1d4bdb26 | 1 years ago (raw) | root | parent | reply | flag 
 @c65b183b @4c603b88 @462ebf4c depends :)  add #:declarative? #f to the define-module of X and see
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Grigory Shepelev | 1 years ago (raw) | root | parent | reply | flag 
 @c39d2605 won't help :(
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735cb917 | 1 years ago (raw) | root | parent | reply | flag 
 @c65b183b @c39d2605 @4c603b88 @462ebf4c 

So you want to update the closure of f?
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Grigory Shepelev | 1 years ago (raw) | root | parent | reply | flag 
 @338f82ef @c39d2605 @4c603b88 @462ebf4c 

I'm not sure about this formulation. I want to update `x` from `(X)` "globally": in a way that everything from `(X)` that'd have `x` referenced would also update it to the new value.