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 If E pushes the stone, who experiences the worst outcome? https://image.nostr.build/d6a606a7a832a8edd7bd50239cc304c016bbbf29bb7446d6d7b412b71f7ad3db.jpg  
 E because he killed someone 
 Either D or E

- D if he's tall enough (lol)
- E when the boulder shoots back at himself  
 E, he's a cunt 
 D, and then if the peed is high enough, that poor lizard is going to get it. 
 C.

HES THE ONLY ONE THAT DIES.

THE BOULDER WILL NEVER REACH A
B HAS ROOM TO DUCK
C DIES.
D HAS A NEWR MISS.
E Was trying to stop the Boulder. 🤣
 
 Does he though if the rolling boulder is lighter than the static boulder and a horizontal force is being applied to the seesaw instead of a vertical force? 
 We don't have any way of knowing that from the evidence given. 
 True. Does that mean we can't definitively say that C dies either? 
 If we only assume 3 things; that E is pushing the Boulder, each boulder is made out of the same material based on its shading, nobody can move;

A won't get touched.
B will be trapt.
C will be severely injured or die
D will live due to the gap in the moving Boulder.
E will live because he pushed it.

 
 D just gotta duck and he’ll be fine. C is fukt. A & B will be fine because they can see it all coming.

Literally just the bloke C who is about to be impaled by a torture seesaw. 
 There's a possibility that the moonshaped horn thing gets stuck in the hole and doesn't reach C, or that it loses speed and because it's missing that chunk and it's lighter, it's weight is insufficient to move the lever.

I'm an optimist. 
 I think you’re supposed to do the math based on the slope and shit of where the wedge will roll over D. That’s why they give you the triangle dimensions for the slope.

But if it passes D then C is fukt. Speed won’t matter, he’s got an inverse seesaw ready to Saw him with any weight applied to the muppet laying down underneath a bunch of spikes ready to impale him. https://i.nostr.build/nmKNL4MJ4yJ1RmJC.jpg  
 Yeah, I saw the lines and assumed that was the expectation. To which I say
https://nostrcheck.me/media/82bdee506e769ebc94ee2f362d07c1960dce40bac650d826a42f8e0c019c3c96/039554af422e07e81d91d8ac4da937cf7840994c8d9cf0ce522559041bbffe9d.webp 
 Oh, now that I think better about it, that's the function of the horseshoe shape. It must fit on D's head, so he doesn't even need to duck. 
 You could do the math. You could even outsource it to an LLM to do it for you. 

But I like that you’re here with me just riding the vibe that D will be ok and work it out! 
 D is our boy. Nothing can touch him. No math required. 
 D and C. They'll shit their pants. The stone with the recess (S1) has less mass than the solid stone (S2) on the seesaw. The momentum of S1 will neither be enough to tip the seesaw nor to injure C. This means that B will not be injured either. 
 C and E. D will survive, just duck or trust the maths. The rock on the end of the catapult is going to go through the air and lands on E who pushed the rick to begin with.