Oddbean new post about login | logout @surk... @buy robux today :ROBUX: @974dd529 awk '$0=$2'
@menherahair @surk... @974dd529 @buy robux today :ROBUX: awk '/pernias_passwords/{print $2}'
@Yukkuri @974dd529 @buy robux today :ROBUX: @surk... why not awk '$0=$2 && /pernias_passwords/'
@menherahair @974dd529 @buy robux today :ROBUX: @surk... That would be true (1), but in reverse order should be fine.
@Yukkuri @974dd529 @buy robux today :ROBUX: @surk... it doesn't skip the lines with no second field, so you can't look for files named 4096 I guess
@menherahair @974dd529 @buy robux today :ROBUX: @surk... That can be work-arounded by predicating on NF: awk '/pernias_passwords/ && NF >= 2 && $0=$2', but It also won't handle files with whitespaces and newlines in names properly. find . -path '*pernias_passwords*' -exec du -a {} \; might be required.
@Yukkuri @974dd529 @buy robux today :ROBUX: @surk... NF >= 2 && $0=$2’ this check on NF does nothing here, $0=$2 is already false if second field doesn’t exist to deal with whitespace in du output specifically, I guess it makes sense to just remove the first field instead, but then we can’t use that statement as the condition. du -a | awk '/pernias_passwords/{$1=""; print}' or to not match in filesizes: du -a | awk '{$1=""; if(/pernias_passwords/)print}' on a side note, what I posted before actually won’t fly because of operator precedence. should be awk '($0=$2) && /pernias_passwords/' ok I’m ready to sleep now gn